Wagering requirements: a calculation you can do yourself
A wagering requirement says how many times you must stake a bonus before you can withdraw it. This page shows how to turn it into a stake total for the game you will actually play, and what that total means given the game's return.
The formula
Stakes needed = base × multiple ÷ game contribution. The base is the bonus, or bonus plus deposit. The contribution is the share a game counts (100% = 1, 10% = 0.1).
| Example | Base | Multiple | Contribution | Stakes needed |
|---|---|---|---|---|
| Slot | 50 | 30× | 100% | 1,500 |
| Slot, bonus + deposit | 100 | 30× | 100% | 3,000 |
| Table game | 50 | 30× | 10% | 15,000 |
The examples are illustrative; the multiple and contribution for your offer are in its terms.
Expected loss during wagering
On every stake the game keeps, on average, the difference to 100% return. At 96% that is 4%. On 1,500 of stakes the expected loss is about 60. If the bonus is 50, the expected value is negative. With lower wagering or a higher return the balance improves, which is why the return shown in the game's info screen is an important part of the calculation.
Volatility and the chance of finishing
Expected loss is an average. With a high-volatility game many players lose the bonus before the end of wagering while a few finish with a larger sum. With low volatility results cluster around the average. Choose volatility according to whether finishing matters more to you, or the chance of a bigger outcome.
Deadline and pace
Deadlines are often seven to thirty days. Staking 1,500 in seven days means over 200 a day; at 0.50 a spin that is more than 400 spins daily. A pace like that means long sessions you may not have planned, and it is as important a part of the assessment as the multiple itself.
Frequently asked questions
Do my own-money stakes count?
Does a feature buy count?
How do I know how much wagering is left?
Related
The size, terms and availability of bonuses depend on the operator, country and account, and they change. The version in the operator's own terms is always the one that applies.
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